If 15 grams of iron react thus: Fe + H2SO4 = FeSO4 + H2, how many liters of hydrogen are liberated at normal conditions?
Explanation
This problem consists of three parts:
Question 1
Concepts
stoichiometry, mole concept, molar volume of gases (at STP), chemical equations
Explanation
The reaction: Fe+H2SO4→FeSO4+H2 shows that 1 mole of iron produces 1 mole of hydrogen gas. Using the molar mass of iron, we can find moles of Fe and thus moles (and volume) of H₂ evolved.
Step-By-Step Solution
Step 1: Calculate moles of Fe
Given, mass of Fe = 15 g. Molar mass of Fe = 55.85 g/mol.Number of moles of Fe = 55.8515=0.2686 mol (rounded to 4 decimal places).
Step 2: Moles of H₂ liberated
According to the balanced equation, 1 mol Fe → 1 mol H₂. So, moles of H₂ = 0.2686 mol.
Step 3: Convert moles of H₂ to volume (at NTP)
At NTP (Normal conditions: 0°C, 1 atm), 1 mol of gas = 22.4 L.Volume of H₂ = moles × molar volume = 0.2686 × 22.4 = 6.016 L.
Final Answer
6.02 liters (rounded to 2 decimal places) of H2 are liberated at normal conditions.
Question 2
Concepts
ideal gas law, Dalton's Law of Partial Pressures, conversion from mass percent to mole (volume) percent, molar mass
Explanation
To convert mass % to volume (mole) %, use:Given composition by weight:
Step-By-Step Solution
Step 1: Calculate moles of each component
Molar masses:Moles of Cl₂ = 67 / 70.90 = 0.945 mol Moles of Br₂ = 28 / 159.8 = 0.175 mol Moles of O₂ = 5 / 32.00 = 0.156 mol
Step 2: Total moles
Total moles = 0.945 + 0.175 + 0.156 = 1.276 mol
Step 3: Volume (mole) % of each gas
Final Answer
Composition by volume:
Question 3
Concepts
ideal gas law, density of gases, partial pressure, molar mass, Dalton's law
Explanation
Density (d) can be calculated using the formula: d=RTPM where
Step-By-Step Solution
Step 1: Calculate average molar mass (M) of the gas mixture
Mole fractions:Average M=(0.741×70.90)+(0.137×159.8)+(0.122×32.00) =52.55+21.89+3.90=78.34g/mol
Step 2: Convert pressure and temperature to correct units
Step 3: Apply ideal gas law for density
d=RTPM=0.0821×298.150.974×78.34Calculate denominator:Numerator:d=24.48276.30=3.12g/L
Final Answer
Density of the mixture at 25°C and 740 mm Hg: 3.12g/L
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