If 15 grams of iron react thus: Fe + H2SO4 = FeSO4 + H2, how many liters of hydrogen are liberated at normal conditions?

Explanation

This problem consists of three parts:

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Question 1

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Concepts

stoichiometry, mole concept, molar volume of gases (at STP), chemical equations

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Explanation

The reaction: Fe+H2​SO4​→FeSO4​+H2​ shows that 1 mole of iron produces 1 mole of hydrogen gas. Using the molar mass of iron, we can find moles of Fe and thus moles (and volume) of H₂ evolved.

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Step-By-Step Solution

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Step 1: Calculate moles of Fe

Given, mass of Fe = 15 g. Molar mass of Fe = 55.85 g/mol.Number of moles of Fe = 55.8515​=0.2686 mol (rounded to 4 decimal places).

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Step 2: Moles of H₂ liberated

According to the balanced equation, 1 mol Fe → 1 mol H₂. So, moles of H₂ = 0.2686 mol.

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Step 3: Convert moles of H₂ to volume (at NTP)

At NTP (Normal conditions: 0°C, 1 atm), 1 mol of gas = 22.4 L.Volume of H₂ = moles × molar volume = 0.2686 × 22.4 = 6.016 L.

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Final Answer

6.02 liters (rounded to 2 decimal places) of H2​ are liberated at normal conditions.

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Question 2

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Concepts

ideal gas law, Dalton's Law of Partial Pressures, conversion from mass percent to mole (volume) percent, molar mass

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Explanation

To convert mass % to volume (mole) %, use:Given composition by weight:

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Step-By-Step Solution

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Step 1: Calculate moles of each component

Molar masses:Moles of Cl₂ = 67 / 70.90 = 0.945 mol Moles of Br₂ = 28 / 159.8 = 0.175 mol Moles of O₂ = 5 / 32.00 = 0.156 mol

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Step 2: Total moles

Total moles = 0.945 + 0.175 + 0.156 = 1.276 mol

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Step 3: Volume (mole) % of each gas

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Final Answer

Composition by volume:

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Question 3

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Concepts

ideal gas law, density of gases, partial pressure, molar mass, Dalton's law

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Explanation

Density (d) can be calculated using the formula: d=RTPM​ where

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Step-By-Step Solution

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Step 1: Calculate average molar mass (M) of the gas mixture

Mole fractions:Average M=(0.741×70.90)+(0.137×159.8)+(0.122×32.00) =52.55+21.89+3.90=78.34g/mol

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Step 2: Convert pressure and temperature to correct units

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Step 3: Apply ideal gas law for density

d=RTPM​=0.0821×298.150.974×78.34​Calculate denominator:Numerator:d=24.48276.30​=3.12g/L

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Final Answer

Density of the mixture at 25°C and 740 mm Hg: 3.12g/L​

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